{"id":18842,"date":"2022-06-28T13:39:15","date_gmt":"2022-06-28T13:39:15","guid":{"rendered":"https:\/\/www.kite47.com\/?p=18842"},"modified":"2022-06-28T13:48:38","modified_gmt":"2022-06-28T13:48:38","slug":"you-to-litre-regarding-water-consists-of-ten-mol","status":"publish","type":"post","link":"https:\/\/kite47.com\/index.php\/2022\/06\/28\/you-to-litre-regarding-water-consists-of-ten-mol\/","title":{"rendered":"You to litre regarding water consists of ten mol hydrogen ions"},"content":{"rendered":"<p><title>You to litre regarding water consists of ten mol hydrogen ions<\/title><\/p>\n<p>Question 51. The degree of ionisation in water will be &#8230;&#8230;&#8230;&#8230;&#8230;. (a) 8 x 10 -7 (b) 0.8 x 10 -9 (c) 3.6 x 10 -7 (d) 3.6 x 10 -9 Answer: (a) 8 x 10 -7 Solution: 1 litre of water contains mole. So, degree of ionisation = \\(\\frac <10^<-7>\\times 18><1000>\\) = 1.8 x 10 -7<\/p>\n<h2>COOH services?<\/h2>\n<p>Question 52. If the solubility product of lead iodide (PbI<sub>2<\/sub>) is 3.2 x 10 -8 . Then its solubility in moles\/litre will be &#8230;&#8230;&#8230;&#8230;. (a) 2 x 10 -3 . (b) cuatro x 10 -4 (c) 1.6 x 10 -5 (d) 1.8 x 10 -5 Solution: K<sub>sp<\/sub> = 4s 3 4s 3 = 3.2 x 10 -8 s = 2 x 10 -3 M<\/p>\n<h2>Concern 54<\/h2>\n<p>Question 53. The pH of a soft drink is 3.82. It&#8217;s hydrogen ion concentration will be &#8230;&#8230;&#8230;&#8230;&#8230; (a) 1.96 x 10 -2 mol \/ L (b) 1.96 x 1o -3 mol \/ L (c) 1.5 x 10 -4 mol \/ L (d) 1.96 x 10 -1 mol \/ L Answer: (c) 1.5 x 10 -4 mol \/ L Solution: pH = 3.82 = \u2013 log<sub>10<\/sub>[H + ] ? [H + ] = 1.5 x 10 -4 mol \/ litre<\/p>\n<p>The pH of a solution at 25\u00b0C containing 0.10 M sodium acetate and 0.03 M acetic acid is &#8230;&#8230;&#8230;&#8230;.. (pK<sub>a<\/sub> for CH<sub>3<\/sub>COOH = 4.57) (a) 4.09 (b) 5.09 (c) 6.10 (d) 7.09 Answer: (b) 5.09 Solution: pH = pK<sub>a<\/sub> + log \\(\\frac < [salt]>< [acid]>\\) = 4.57 + log \\(\\frac < 0.10>< 0.03>\\) = 5.09<\/p>\n<p>Question 55. A weak acid is 0.1% ionised in 0.1 M solution. Its pH is &#8230;&#8230;&#8230;&#8230;.. (a) 2 (b) 3 (c) 4 (d) 1 Answer: (c) 4 Solution: For a monobasic acid [H + ] = c.? = \\(\\frac < 1>< 2>\\) x 0.001 = 10 -4 pH = \u2013 log<sub>10<\/sub>[10 -4 ] = 4<\/p>\n<p>Question 56. Which one of the following is not a buffer solution? (a) 0.8 M H<sub>2<\/sub>S + 0.8 M KHS. (b) 2 M C<sub>6<\/sub>H<sub>5<\/sub>NH<sub>2<\/sub> + 2 M C<sub>6<\/sub>H<sub>5<\/sub>N (c) 3 M H<sub>2<\/sub>CO<sub>3<\/sub> + 3 M KHCO<sub>3<\/sub> (d) 0.05 M KCIO<sub>4<\/sub> + 0.05 M HCIO Answer: (d) 0.05 M KCIO<sub>4<\/sub> + 0.05 M HCIO Hint. HClO<sub>4<\/sub> is a strong acid while buffer is a mixture of weak acid and its salt.<!--more--><\/p>\n<p>Question 57. The pH of pure water or neutral solution at 50\u00b0C is &#8230;&#8230;&#8230;&#8230;&#8230; (pK<sub>w<\/sub> = at 50\u00b0C) (a) 7.0 (b) 7.13 (c) 6.0 (d) 6.63 Answer: (d) 6.63 Solution: [H + ] [OH \u2013 ] = 10 &#8211; [H + ] = [OH \u2013 ] [H + ] = \\(\\frac < <>^< \\frac> < 2>> >< 2>\\) ? pH = 6.63<\/p>\n<p>Question 59. What is the pH of 1 M CH<sub>3<\/sub>. Ka of acetic acid is 1.8 x 10 -5 . K = 10 -14 mol 2 litre 2 . (a) 9.4 (b) 4.8 (c) 3.6 (d) 2.4 Answer: (a) 9.4 Solution: CH<sub>3<\/sub>COO + H<sub>2<\/sub>O \\(\\rightleftharpoons\\) CH<sub>3<\/sub>COOH + OH \u2013 [OH \u2013 ] = c x h<\/p>\n<p>= 2.thirty-five x ten -5 pOH = 4.62 pH + pOH = 14 pH = fourteen \u2013 4.62 = 9.38<\/p>\n<p>Question 60. 4Na + O<sub>2<\/sub> > 2Na<sub>2<\/sub>O Na<sub>2<\/sub>O + H<sub>2<\/sub>O > 2NaOH In the given reaction, the oxide of sodium is &#8230;&#8230;&#8230;&#8230;.. (a) Acidic (b) Basic (c) Amphoteric (d) Neutral Answer: (b) Basic Solution. Na<sub>2<\/sub>O form NaOH so that it is basic oxide.<\/p>\n<p>Concern 61. New pH off 0.001 Yards NaOH might be &#8230;&#8230; <a href=\"https:\/\/datingranking.net\/escort-directory\/round-rock\/\">site there<\/a>&#8230;&#8230;. (a) step 3 (b) 2 (c) eleven (d) a dozen Respond to: (c) eleven Provider: 0.001 Yards NaOH setting [OH \u2013 ] 0.001 . ten -step 3 pOH = 3 pH + pOH = fourteen pH = fourteen \u2013 3 = 11<\/p>\n","protected":false},"excerpt":{"rendered":"<p>You to litre regarding water consists of ten mol hydrogen ions Question 51. The degree of ionisation in water will be &#8230;&#8230;&#8230;&#8230;&#8230;. (a) 8 x 10 -7 (b) 0.8 x 10 -9 (c) 3.6 x 10 -7 (d) 3.6 x 10 -9 Answer: (a) 8 x 10 -7 Solution: 1 litre of water contains mole.<a class=\"read-more\" href=\"https:\/\/kite47.com\/index.php\/2022\/06\/28\/you-to-litre-regarding-water-consists-of-ten-mol\/\"> [&hellip;]<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":[],"categories":[2559],"tags":[],"_links":{"self":[{"href":"https:\/\/kite47.com\/index.php\/wp-json\/wp\/v2\/posts\/18842"}],"collection":[{"href":"https:\/\/kite47.com\/index.php\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/kite47.com\/index.php\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/kite47.com\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/kite47.com\/index.php\/wp-json\/wp\/v2\/comments?post=18842"}],"version-history":[{"count":1,"href":"https:\/\/kite47.com\/index.php\/wp-json\/wp\/v2\/posts\/18842\/revisions"}],"predecessor-version":[{"id":18843,"href":"https:\/\/kite47.com\/index.php\/wp-json\/wp\/v2\/posts\/18842\/revisions\/18843"}],"wp:attachment":[{"href":"https:\/\/kite47.com\/index.php\/wp-json\/wp\/v2\/media?parent=18842"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/kite47.com\/index.php\/wp-json\/wp\/v2\/categories?post=18842"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/kite47.com\/index.php\/wp-json\/wp\/v2\/tags?post=18842"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}